Longest run of consecutive 1s in a binary array. [1,1,0,1,1,1,0,1,1] → 3.
(LeetCode 485)
class Solution {public: int findMaxConsecutiveOnes(vector<int>& nums) { int count = 0; int maxCount = 0;
for (int i = 0; i < nums.size(); i++) { if (nums[i] == 1) { count++; } else { maxCount = std::max(maxCount, count); count = 0; } }
// Final comparison in case the array ends with a run of 1s maxCount = std::max(maxCount, count);
return maxCount; }};Time: O(n). Space: O(1). The final comparison after the loop matters — without it, a
trailing run of 1s (with no 0 after it) would never get counted.